Want to show: √12 is irrational

After plugging in p=3n, we get 9n²=12q². This allows us to conclude that n is divisible by 2.

After plugging in p=3n, we get 9n²=12q². This allows us to conclude that n is divisible by 3.

After plugging in p=3n, we get 9n²=12q². This allows us to conclude that q is divisible by 3.